x^2+5/2x+c=0

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Solution for x^2+5/2x+c=0 equation: 


x in (-oo:+oo)

c+x^2+(5/2)*x = 0

c+x^2+5/2*x = 0

DELTA = (5/2)^2-(1*4*c)

DELTA = 25/4-4*c

25/4-4*c = 0

25/4-4*c = 0 // - 25/4

-4*c = -25/4 // : -4

c = -25/4/(-4)

c = 25/16

DELTA = 0  <=>  t_1 = 25/16

x = -5/2/(1*2) i c = 25/16

x = -5/4 i c = 25/16

( x = ((25/4-4*c)^(1/2)-5/2)/(1*2) or x = (-(25/4-4*c)^(1/2)-5/2)/(1*2) ) i c > 25/16

( x = ((25/4-4*c)^(1/2)-5/2)/2 or x = (-((25/4-4*c)^(1/2)+5/2))/2 ) i c > 25/16

c-25/16 > 0

c-25/16 > 0 // + 25/16

c > 25/16

x in { -5/4, ((25/4-4*c)^(1/2)-5/2)/2, (-((25/4-4*c)^(1/2)+5/2))/2 }

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